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suppliers of TMS320VC5510GGWA1 and PDF data of TMS320VC5510GGWA1

Part Numbert Mfg Packt D/C Descriptiont Qty Company/Contact  
TMS320VC5510GGWA1     3500    Texas Instruments 
    Jetli Electronic HK Limited
  • Contact:Jetchan
  • Tel:86-754-84445458
  • Fax:86-754-84445458
  • Email: jetli@jetlielec.com


TMS320VC5510GGWA1 TI/BB    08+  New  3265 
    SHENZHEN GAOHANG TECHNOLOGY CO..
  • Contact:lin
  • Tel:86-755-82727788
  • Fax:86-755-82727688
  • Email: weifengic@163.com
TMS320VC5510GGWA1 TIS        97 

TMS320VC5510GGWA1 Datasheet
The serial port can operate in 4 modes: Mode 0: Serial l/0 expansion mode. Serial data enters and exits through RxDn. TxDn outputs the shift clock. 8 bits are transmitted/received (LSB first). (The baud rate is fixed at l/16 the oscillator frequency.) Mode l: Standard 8-bit UART mode. 10 bits are transmitted (through TxDn) or received (through RxDn): a start bit (0), 8 data bits (LSB first), and a stop bit (1). On receive, the stop bit goes into RB8 in Special Function Register SnCON. The baud rate is variable Mode 2: Fixed rate 9-bit UART mode. 11 bits are transmitted (through TxD) or received (through RxD): start bit (0), 8 data bits (LSB first), a programmable 9th data bit, and a stop bit (1). On Transmit, the 9th data bit (TB8_n in SnCON) can be assigned the value of o or l. Or, for example, the parity bit (P, in the PSW) could be moved into TB8_n. On receive, the 9th data bit goes into RB8_n in Special Function Register SnCON, while the stop bit is ignored. The baud rate is programmable t0 1/32 0f the oscillator frequency.
TMS320VC5510GGWA1 Price

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TMS320VC5510GGWA1 on stock

Parameter Symbol Minimum Maximum Units Note
Supply Voltage VCC -0.5 +5.5 V l
Supply Voltage VNEG -10 +0.5 V


Items Symbols Test Conditions Min Typ. Max. Units
]9.N- VcBo lcao - ImA 1200 V
]L·i 'y VCEO ICEO-lmA 1200 V
VCEO<SlJSI _ V
]L--~y k/CESUS} VE= -3V l 1200 V
i v9^ VEa0 lEBo=200mA 10 V
]L lCe0 VCBO= 1200V 1 0 mA
Ii-y EBO VEao-lOV 200 mA
]L·i-y -VCEO IECO= 50A 2 0 V
hFE lc=50A, VCE=4V, Ti=125'C 500
]L-{-y VCEtsatl lc - 50A 4.0 V
K·-y VBElsatl lB = 0. 1A 4 5 V
ton lc - 50A 3 5 S
r-y> tatZ IBI=O . 1A 15 0 S
tf IB2= -1.OA 3 0 S
Ed IBl = +O . 1A, IBZ = - L . OA, Pw = 50us 750 V